[{(a² + b²)/2ab} - 1] ÷ [{(a³ - b³)/(a - b)} - 3ab] = কত?

A ab

B 1

C 1/2ab

D 2ab

Correct Answer: Option C

[{(a² + b²- 2ab)/2ab} ÷ [{a³ - b³- 3ab(a - b)}/(a - b)]
[(a - b)²/2ab]÷ [{(a - b)³}/(a - b)]
[(a - b)²/2ab] ×[(a - b)/(a - b)³]
= 1/2ab

[{(a2 + b2)/2ab} - 1] ÷ [{(a3 - b3)/(a - b)} - 3ab] = কত?